r8c7 must be a 9 (only place on the pipe for it) r4c2 must be a 2 (31 - a single digit) r7c6 = 6 (sudoku) r8c3 = 6 (sudoku)
Step 6 : Box 4
Length 2 arrow with no digit "2" or "3" is a minimum of 5 Which makes the node on row 4 a max of 26 (but 6 is not possible, so 25) Minimum is 21, but that still makes the pipe from it have only "4" or higher.
Step 7 : Matching nodes
5/6/7/9 + 1/3/4/5 = 11 valid pairs are: 6+5, 7+4
1/4/5 + 4/5 = 6/7 valid pairs are 5+1 = 6
That puts 25 in the other node, and the only way to make it in 3 cells is 8,8,9
r2c1 is 4/8/9 r3c2 is 3/4/5/6/7/9 Which would leave r1c2 as minimum 7 However we can also eliminate any combo that adds to more than 9 Valid combos = 4+3=7 and 4+5=9
Which makes the other node 25 - (7 or 9) = 16 or 18